# Intergral Partial Fraction

With the previous method
we cannot (will be difficult) to neutralize the forms as below

∫ 5x (2x – 4) dx or ∫ 2x sin x dx.

To solve the form of the equation, let us consider the following steps.

If

**f**and**g**are differential functions, the rule applies.
If we integrate the rule, we will get it

To further simplify the form we can write it with

u = f(x) du = f ’(x) dx

v = g(x) dv = g ‘(x) dx

so, the formula can be simplified as follows.

**∫ u dv = uv - ∫ v du**

**Example 1.**

Solve the integral results of ∫ 12x (2x - 3)

^{3}dx
Answer:

If it is known that,

So that,

**Example 2.**

Solve the integral results of ∫ 12x (2x - 3)

^{3}dx
Answer:

If it is known that,

So that,

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When fractions are being divided, as a fraction you need to "flip" the second fraction and change the operation sign from division to multiplication. 7/11 now becomes 11/7. You will now multiply the fractions.

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